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4.9x^2-8x=30
We move all terms to the left:
4.9x^2-8x-(30)=0
a = 4.9; b = -8; c = -30;
Δ = b2-4ac
Δ = -82-4·4.9·(-30)
Δ = 652
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{652}=\sqrt{4*163}=\sqrt{4}*\sqrt{163}=2\sqrt{163}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-2\sqrt{163}}{2*4.9}=\frac{8-2\sqrt{163}}{9.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+2\sqrt{163}}{2*4.9}=\frac{8+2\sqrt{163}}{9.8} $
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